Unit 2:Day 6

Today, students will learn ALL about Special Right Triangles! Isn't that awesome!

There is 2 types of special right triangles=

45–45–90 triangle

30–60–90 triangle

When solving for problems involving special right triangles, you need to have a calculator and always remember SOHCAHTOA or the pythagorean theorem. 

As SOH= Sin-opposite and Hypotenuse
CAH= Cos-Adjacent and Hypotenuse
TOA= Tan-Opposite +Adjacent

Quiz

ONLY DO 1-3

ANSWERS


1) So Here we are trying to find missing angles. We have and adjacent and an hypotenuse side. So we use COS-1=12/13. So 12 divided by 13 by COS-1.    22.6

2) Here we have an opposite and an adjacent side. So we use Tan-1=4/13
so 4 divided by 13 by TAN-1    17.1

3) Here we have a Hypotenuse and an adjacent angle, so we are using COS. So COS-1=6/9. 6 divided by 9 times COS-1 is....... 48.2